Question

The sum of the digits of a two digit number is 11 . If 63 is subtracted from the number, the digit get interchanged. What is the number?

Answer 1

Answer:

${\sf{\boxed{\boxed{\underline{Number= 92}}}}}$

Explanation:

Let the tens digit be x

and the unit digit be 11-x

Given:

The digit will get interchanged when we'll minus 63 from it.

we got an equation:

[10(x)+(11-x)] - 63 = 10(11-x) + x.

Solution:

⇒ $\sf[10(x)+(11-x)]-63=10(11-x)+x.$

⇒ $\sf[9x+11]-63=110-9x$

⇒ $\sf9x+9x=110+52$

⇒ $\sf18x=162$

⇒ $\sf x=\frac{162}{18}$

⇒ $\sf x=9$

unit digit (11-x) = 2

tens digit (x) = 9

Number = 92

Answer 2

Answer

Solution

$=[10x+11-x]-63=10(11-x)+x</strong></p><p></p><p><strong>[tex]=[10x+11-x]-63=10(11-x)+x=[9x+11]-63=110-9x</strong></p><p><strong>[tex]=[10x+11-x]-63=10(11-x)+x=[9x+11]-63=110-9x=9x+9x$

$= 110 + 52$

$= 18x = 162$

$x = 162 \div 18$

$x = 9$

$11 - 9 = 2$

$tens \: digit = 9$

$number = 92$