Question

l and m are two parallel lines intersected by
another pair of parallel lines p and q
(see Fig. 7.19). Show that triangle ABC=triangleCDA.​

Answer 1

❄️ Question :-

l and m are two parallel lines intersected by another pair of parallel lines p and q. Show that ∆ABC =~ ∆CDA.

❄️ Solution :-

✍️Given :- l and m are two parallel lines intersected by p and q.

✍️To prove :- We have to prove that ∆ABC =~ ∆CDA.

✍️Proof :-

In ∆ABC and ∆CDA,

AC = AC [Common side]

<CAB = <ACD [Alternative interior angles because l || m]

<ACB = <CAD [Alternative interior angles l || m]

$\green \mapsto$ By ASA congruence rule,

∆ABC =~ ∆CDA.

✍️Hence proved !

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Hope you have a beautiful day ❤️

Answer 2

Step-by-step explanation:

⭐Question :-

l and m are two parallel lines intersected by another pair of parallel lines p and q. Show that ∆ABC =~ ∆CDA.

⭐Solution :-

✍️Given :- l and m are two parallel lines intersected by p and q.

✍️To prove :- We have to prove that ∆ABC =~ ∆CDA.

✍️Proof :-

In ∆ABC and ∆CDA,

AC = AC [Common side]

<CAB = <ACD [Alternative interior angles]

<ACB = <CAD [Alternative interior angles]

↦ By ASA congruence rule,

∆ABC =~ ∆CDA.

Hence proved !❤❤

✡