Math, asked by adityachauhan3793, 9 months ago

L.C.M(x,18) =36 & H.C.F(x,18)=2, then x is *​

Answers

Answered by Skyllen
11

Given:-

  • LCM = 36
  • HCF = 2
  • Numbers = x and 18

To find:-

  • Value of number x

Solution:-

 \boxed{  \small{ \bf{product \: of \: two \: numbers = hcf \times lcm}}}

 \sf  \implies \: x \times 18 = 36   \times 2

 \sf \implies \: x =  \dfrac{36 \times 2}{18}

 \sf \implies \:  x =  \dfrac{72}{18}

 \sf \implies    \small{\boxed{\boxed{\boxed{  \purple{\bf{x = 4}}}}}}

∴ Value of number x is 4.

Related info:-

HCF = highest common factor

LCM = lowest common factor

According to property of LCM and HCF, the product of LCM and HCF is equivalent to the product of the two given natural numbers.

Formula=> Product of two number = product of LCM and HCF.

Answered by Anonymous
12

Question :-

LCM (x,18) =36 and HCF (x,18)=2 , then find the x ?

Answer :-

Given that :

  • LCM = 36
  • HCF=2
  • OTHER NUMBERS = x and 18

What we have to find here ?

=> we have to find the value of x .

How to find it ?

=> we can simply found the value of x by putting the formula of HCF X LCM = product of two numbers .

Answer :-

=> x × 18 = 36 × 2

=> x =36×2/18

=> x=72/18

=> x =4

Hence ,

the value of x is 4 .

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