l kg of water and 250 g of water at 60℃.l kg of water raise of temperature .both become termal equilibrium.
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(m1+m2)s T=m1L+m2sT1=1000×80+4400×1×10
5400×1×T=8000+44000=52000
T=52000/5400=520/54=9.63° C
[FinaltemperatureT=[m1 L+m2s T1]/(m1+m2) s]
5400×1×T=8000+44000=52000
T=52000/5400=520/54=9.63° C
[FinaltemperatureT=[m1 L+m2s T1]/(m1+m2) s]
kk24:
I don't know please ask any others guy
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hey mate here is your answer
=9.63 degrees
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