Question

(l+m)^2-4lm factorise​

Answer 1

(l-m)2 is the answer

first solve (l-m)^2 then minus by -4lm

Answer 2

Aɴsᴡᴇʀ :-

(l + m)2 – 4lm

Expanding (l + m)2, we get

l2 + 2lm + m2 – 4lm

= l2 – 2lm + m2

= l2 – Im – lm + m2

= l(l – m) – m(l – m)

= (l – m) (l – m)

= (l – m)2