L,m, and p can do a piece of work in 15,20 and 40 days respectively.They started the work together.M left the work after 4 days of starting and p left the work before 3 days of completion.In how many days the work will be completed?
Answers
in 105/11 Days work will be completed
Step-by-step explanation:
L,m, and p can do a piece of work in 15,20 and 40 days respectively
L 1 day work = 1/15
M 1 day work = 1/20
P 1 Day work = 1/40
L , M & P 1 day work together = 1/15 + 1/20 + 1/40
= (8 + 6 + 3)/120
= 17/120
M left the work after 4 days of starting
Work done in 4 Day = 4 * 17/120 = 17/30
Remaining work = 1 - 17/30 = 13/30
P left the work before 3 days of completion
=> LAst 3 Days L only workes
L 3 Days work = 3 * 1/15 = 1/5
Work Done by L & P = 13/30 - 1/5
= (13 - 6)/30
= 7/30
L & P together 1 Day work = 1/15 + 1/40 = (8 + 3)/120
= 11/120
L& P worked for (7/30)/(11/120) = 28/11
Total number of days = 4 + 28/11 + 3
= (44 + 28 + 33)/11
= 105/11 Days
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