Question

l² + 2² +3² + ...+ x² = x ( x+ 1 ) ( 2x+1 ) /6 hai, to 1² + 3² +5² + ...+ 19² barabar hai

Answer 1

1^2 +2^2 +3^2 ........+19^2 = 19 (19+1) (2×19+1)/6
= 19 ×20 × 39 /6 = 14820 /6
= 2470

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