Question

l²+m²+l²m²+1
......pls factorise fast​

Answer 1

$\bf\large\underline\pink{Solution:-}$

♦ 100 - a² - b² - 2ab

= (10)² - (a² + b² + 2ab)

= (10)² - (a + b)²

= [10 + (a + b)] [10 - (a + b)

= (10 + a + b) (10 - a - b)

Answer - (10 + a + b) (10 - a - b)

Identity Used -

♢ a² + b² + 2ab = (a + b)²

♢ a² - b² = (a + b) (a - b)

Note -

(10)² = 100

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Answer 2

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