Question

Lalita can walk at 6m/s or cycle at 25m/s. To cover a distance of 650m using a combination of the two modes of transport , she takes 45s . How long did lalita cycle?

Answer 1

Speed she has of walking = 6 m/s

Let time taken on walking be p

Speed she has on cycle = 25 m/s

Let time taken on cycle be q

So, we have following equations

6p + 25q = 650

p + q = 45

So, p = 45 - q

Putting this in 1st equation, we get

6(45 - q) + 25q = 650

270 - 6q + 25q = 650

270 + 19q = 650

19q = 650 - 270

q = 380/19

q = 20

So, p = 25

Means she: cycled for 20 secs, and walked for 25 secs.

Answer 2

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$\huge\color{orange}\boxed{ANSWER}$

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$<b><i><u>Speed$ she was of walking = 6 m/s

Let time taken on walking be y

Speed she has on cycle = 25 m/s

Let time taken on cycle be x

So, we have following equations
6x + 25x = 650
y + x = 45
So, p = 45 - x

Putting this in 1st equation, we will get

6(45 - x) + 25x = 650
270 - 6q + 25x = 650
270 + 19x = 650
19x = 650 - 270
x = 380/19
x = 20

So, y = 25

Therefore, she cycled for 20 secs, and walked for 25 secs.





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