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The length of a rectangle exceeds its breadth by 5 m. If the breadth were doubled
and the length reduced by 9 m, the area of the rectangle would have increased
140mx Find its dimensions.
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let the breadth(b) of rectangle be X m
then the length (l) = (X + 5) m
area of rectangle = lb
= X(X+5)
according to question,
New Breadth (B) = 2x m
New Length (L) = X + 5 - 9
= (X - 4) m
new area = old area + 140 m
LB = X(X+5)
2x(x-4) = x^2 + 5x
2x^2 - 8x = x^2 + 5x
2x^2 - x^2 = 5x + 8x
x^2 = 13x
x^2 - 13x = 0
X( x- 13) = 0
X - 13 = 0
X = 13 m
Therefore, breadth of rectangule is 13 m and length of rectangule is (13 + 5) = 18 m
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