Question

Laplace inverse of 1/s(s+2)³​

Answer 1

Answer:

We know, for 1s2+(1)2 ,

Laplace −1 is:

Sint u(t) ; Where ωo is 1.

Now, as tnu(t) = n!sn+1

So, Laplace −1 of 1[s2+1]3 is:

2 t2 Sint u(t).

For t > 0, we can write:

2 t2 Sint.

Step-by-step explanation:

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