laplace transform of the signal u(t) is_______
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Explanation: (e-2t – 1)2 = e-4t – 2e-2t + 1
We know that, L {e-at} = \frac{1}{s+a}
L {1} = \frac{1}{s}
∴L {(e-2t – 1)2} = L {e-4t – 2e-2t + 1} = \frac{1}{s+4} – \frac{2}{s+2} + \frac{1}{s}.
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