Largest 4 digit number exacty divisible by 30 and 40
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Let the 4 digit number be x
The largest 4 digit number is 9999
We have asked a number which is divisible by 30 and 40
So,
First we have to find the lcm of 30 and 40
Lcm means least common multiple
So,
Prime factorization of the two numbers is :-
30 = 2*3*5
40= 2*2*2*5
Common numbers is 2 , 5
So,
LCM = 2*5*2*2*3 = 120
Now,
We have to divide the largest 4 digit number with 120
So,
Dividing the numbers
9999/120
So, the quotient is 83
Remainder is 39
So,
We have to subtract the remainder from the largets 4 digit number that is 9999
So,
The number is 9999 - 39 = 9960
So,
The largest 4 digit number divisible by both 30 and 40 is 9960
The largest 4 digit number is 9999
We have asked a number which is divisible by 30 and 40
So,
First we have to find the lcm of 30 and 40
Lcm means least common multiple
So,
Prime factorization of the two numbers is :-
30 = 2*3*5
40= 2*2*2*5
Common numbers is 2 , 5
So,
LCM = 2*5*2*2*3 = 120
Now,
We have to divide the largest 4 digit number with 120
So,
Dividing the numbers
9999/120
So, the quotient is 83
Remainder is 39
So,
We have to subtract the remainder from the largets 4 digit number that is 9999
So,
The number is 9999 - 39 = 9960
So,
The largest 4 digit number divisible by both 30 and 40 is 9960
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