Largest 4-digit number which has a perfect cube?could u explain me the short cut method to do this
Answers
Answered by
0
Solution:-
To find the largest 4 digit number which is a perfect cube, we have to obtain cubes of some natural numbers. Here are the cubes of some natural numbers.
10³ = 10 × 10 × 10 = 1000 ; which is very less than the number we require.
15³ = 15 × 15 × 15 = 3375 ; which is also less than the number we require.
20³ = 20 × 20 × 20 = 8000 ; this is also less than the number we require.
21³ = 21 × 21 × 21 = 9261 ; this is also less than the number we require.
22³ = 22 × 22 × 22 = 10648 ; which is more than the number we require.
So, the required 4 digit number is 9261, which is a perfect cube.
To find the largest 4 digit number which is a perfect cube, we have to obtain cubes of some natural numbers. Here are the cubes of some natural numbers.
10³ = 10 × 10 × 10 = 1000 ; which is very less than the number we require.
15³ = 15 × 15 × 15 = 3375 ; which is also less than the number we require.
20³ = 20 × 20 × 20 = 8000 ; this is also less than the number we require.
21³ = 21 × 21 × 21 = 9261 ; this is also less than the number we require.
22³ = 22 × 22 × 22 = 10648 ; which is more than the number we require.
So, the required 4 digit number is 9261, which is a perfect cube.
Similar questions