Question

Largest number which divides 245 and 1029 leaving remainder 5

Answer 1

Hii friend,

245 -5 = 240

1029-5 = 1024

Prime factorisation of 240 = 2 × 2 × 2 × 2 × 5 × 3

Prime factorisation of 1024 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2.

LCM of 240 and 1024 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 5 = 15360

Therefore,

Required Number = (LCM of 240 and 1024 ) + 5 ] = (15360+5) = 15365 .


HOPE IT WILL HELP YOU...... :-)