last question of the pic ...plzz itz urgent
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diameter of solid spheres=6
r=6/2=3cm
diameter of cylinderical beaker=18
radius= 18/2=9cm
height of raises water=40cm
let the no. of solid spheres put in cylinderical beaker be n
volume of spheres*n=volume of raised water
2/3πr³*n = πr²h
n = πr²h/2/3πr³
n=3r²h/2r³
n=3*9*9*40/2*3*3*3
n=180
no. of solid spheres is 180
r=6/2=3cm
diameter of cylinderical beaker=18
radius= 18/2=9cm
height of raises water=40cm
let the no. of solid spheres put in cylinderical beaker be n
volume of spheres*n=volume of raised water
2/3πr³*n = πr²h
n = πr²h/2/3πr³
n=3r²h/2r³
n=3*9*9*40/2*3*3*3
n=180
no. of solid spheres is 180
kukki4:
thnk yew
mention not
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