Question

Last question on the page that is question 56 please solve 50 points i will mark the correct answer brainliest

Answer 1

The gravitational force acting on the block along the plane is $mgsin\theta$.

Since the block is at rest, and friction is the only other along-the plane force acting on it, its magnitude must be equal to $mgsin\theta$.

For clarity: Answer: (4).

Further notes:

You might have thought that the answer should be $\mu mgcos\theta$ or $\mu mg$ - these are incorrect.

The latter is totally incorrect, since the normal contact force is $mgcos\theta$, and hence the limit of static friction should be $\mu mgcos\theta$. Note also that I said the limit of static friction - which is the maximum magnitude of static friction that could exist between these surfaces.

It is not the force that acts, it is the force that could act at maximum. If friction could stop motion at a lower value, $mgsin\theta$ only, why increase the magnitude? (And instead cause motion?)

Static friction is, like normal contact force, self-adjusting.

Answer 2

Answer:

Explanation:

it is mgsin x

hey resolve the mg component

u get mg sinx and mg cos x

mg cos x will be upwards

mg sin x towards down the slope