Question

Last question please :O

Answer 1

Step-by-step explanation:

let P(X) be the probability of any event x occuring.

Thus, P(X) = no. of times event x occuring/ total no. of trials.

1. P(1) =   three tails/ total outcomes   = 55/350 =  11/70
2. P(2) =  two tials / total outcomes = 95/ 350  =   19/70
3. P(3) =  one tail / total outcomes =   120/ 350 =  24/70
4. P(4) =  no tail/ total outcomes =     80/120      =  16/70

sum of all events = $\frac{ 11 + 19 + 24 + 16}70}$

= 70/70 =1

hence sum of all probabilities is 1.

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Answer 2

Answer:

let P(X) be the probability of any event x occuring.

Thus, P(X) = no. of times event x occuring/ total no. of trials.

P(1) = three tails/ total outcomes = 55/350 = 11/70

P(2) = two tials / total outcomes = 95/ 350 = 19/70

P(3) = one tail / total outcomes = 120/ 350 = 24/70

P(4) = no tail/ total outcomes = 80/120 = 16/70

sum of all events = \frac{ 11 + 19 + 24 + 16}70}

= 70/70 =1

Hence, sum of all probabilities is 1.

Step-by-step explanation:

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