Last Season two running backs on the Steelers football team rushed for a combined total of 1550 yards. One rushed 4 times as many yards as the other. How many yards were rushed by each player.
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Given,
first running back= a
second = b
1st condition,
a + b = 1550 ......(1)
2nd condition,
4a = b .......(2)
Solving by substitution method,
Substituting (2) in (1),
a + 4a = 1550
5a = 1550
a = 1550/5
a = 310 .......(3)
Substituting (3) in (2),
we get,
4(310) = b
b = 1240
So,
the first player ran 310 yards,
the second player ran 1240 yards
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first running back= a
second = b
1st condition,
a + b = 1550 ......(1)
2nd condition,
4a = b .......(2)
Solving by substitution method,
Substituting (2) in (1),
a + 4a = 1550
5a = 1550
a = 1550/5
a = 310 .......(3)
Substituting (3) in (2),
we get,
4(310) = b
b = 1240
So,
the first player ran 310 yards,
the second player ran 1240 yards
Hope it may help you!!!!!!!!!!
Plz mark my answer as brainlest!!!!!!!!
Ayushasutkar:
plz mark my answer as brainlest
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