last tearm of the arithmetic progression 8,15,22 is 218. find the number of tearms.
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Answered by
10
Answer:
find the number of terms. it is 31,the simple technique you can use is minus 1(in this case) from each term and divide by 7(in this case as the difference between 1st and 2nd term is 7, 2nd and 3rd term is 7....) to get no. of terms.
Answered by
5
Answer:
31 terms
Step-by-step explanation:
here First term(a) = 8
common difference(d)=22-15
=15-8
=7
here are nth term (218)=a +(n-1)d
218 =8+(n-1)7
210=(n-1)7
n-1=210/7
n-1=30
n=31
so there are total 31 terms
Hope this will be helpfull:)
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