Lazy Student Problem Description There is a test of Algorithms. Teacher provides a question bank consisting of N questions and guarantees all the questions in the test will be from this question bank. Due to lack of time and his laziness, Codu could only practice M questions. There are T questions in a question paper selected randomly. Passing criteria is solving at least 1 of the T problems. Codu can't solve the question he didn't practice. What is the probability that Codu will pass the test? Constraints 0 < T <= 10000 0 < N, T <= 1000 0 <= M <= 1000 M,T <= N Input Format First line contains single integer T denoting the number of test cases. First line of each test case contains 3 integers separated by space denoting N, T, and M. Output For each test case, print a single integer. If probability is p/q where p & q are co-prime, print (p*mulInv(q)) modulo 1000000007, where mulInv(x) is multiplicative inverse of x under modulo 1000000007. Test Case Explanation Example 1 Input 1 4 2 1 Output 500000004 Explanation The probability is ½. So output is 500000004.
Answers
Answered by
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Language used: Python 3.0
Program:
import math
n=int(input())
for i in range(n):
N,T,M = map(int,input().split(' '))
probability=(1-(math.factorial(N-M))/(math.factorial(T)*math.factorial(N-M)))
#taking in the values of p,q from probability as of p/q
p,q=probability.as_integer_ratio()
#creating the multiple inverse of q
print(pow(q,1000000007-2,1000000007))
Input:
1
4 2 1
Output:
500000004
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