Question

Lcm and hcf is 13 and 403 sum is 221 sum of reciprocals of number?

Answer 1

Answer:

As HCF and LCM is given.

Standard Formula:

Product of two number = HCF*LCM.

Suppose two number be x and y.

xy = 5*12.

x+y = 55.

Now x = 55-y put the value of x in xy = 600.

Now (55-y)y = 600.

y^2-55y+600 = 0.

By factorization we get.

y^2-40y-15y+600 = 0.

y(y-40)-15(y-40) = 0.

Now y=40 and 14.

As in question reciprocal of number 1/x+1/y.

1/40+1/15 = 55/600 = 11/120.

That's it.