Question

lcm and hcf of two numbers are 2970 and 30 prime factors of the product of two numbers are

Answer 1

Let two different numbers are a and b .
A/C to question,
LCM of a and b = LCM{a, b} = 2970
HCF of a and b = HCF{a, b} = 30
we have to find the product of a and b.

we know, HCF{a, b} × LCM{a,b} = a × b
hence, product of a and b = LCM of a and b × HCF of a and b.
= 2970 × 30 = 8910

hence, product of two numbers = 8910

Answer 2

Thank you for asking this question: Here is your answer:

Solution is 2,3,5,11

Factors of [2970] = 2*3*5*3*3*11

Factors of [30] =     2*3*5HCF = 2*3*5 = 30

LCM = 2*3*5*32*11 = 30*99 = 2970

2970 = 2 * 5 * 3 * 3 * 11

30 = 2*3*5

LCM of the two numbers  = 2*3*3*3*5*11 = 2970

So the prime factors are = 2,3,5,11

The correct answer is option A