Question

lcm of 2x^2-3x-2 and x3-4x^2+4x​

Answer 1

Step-by-step explanation:

2x^2–3x-2 =2x^2–4x+x-2 =2x(x-2)+1(x-2) =(2x+1)(x-2)

x^3–4x^2+4x =x(x^2–4x+4) =x(x-2)^2 =x(x-2)(x-2)

LCM =(x-2)(2x+1)x((x-2)

=(2x^2–3x-2)(x^2–2x)

=2x^4–3x^3–2x^2–4x^3+6x^2+4x

=2x^4–7x^3+4x^2+4x. ans

Answer 2

Answer:

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