Question

LCM of addition of 1_3+1_27 please give me answer for this​

Answer 1

Step-by-step explanation:

The first equation given,

x-\frac{1}{x}=5x−

x

1

=5 …….. (i)

If we do the cube of equation (i) we get,

\left(x-\frac{1}{x}\right)^{3}=5^{3}(x−

x

1

)

3

=5

3

x^{3}-\left(\frac{1}{x}\right)^{3}-3 \times x \times\left(\frac{1}{x}\right) \times\left(x-\frac{1}{x}\right)=125x

3

−(

x

1

)

3

−3×x×(

x

1

)×(x−

x

1

)=125

x^{3}-\left(\frac{1}{x}\right)^{3}-3\times(x-\frac{1}{x})=125x

3

−(

x

1

)

3

−3×(x−

x

1

)=125

x^{3}-\left(\frac{1}{x}\right)^{3}-3 \times 5=125x

3

−(

x

1

)

3

−3×5=125

Grouping the terms,

x^{3}-\left(\frac{1}{x}\right)^{3}=125+15x

3

−(

x

1

)

3

=125+15

x^{3}-\left(\frac{1}{x}\right)^{3}=140x

3

−(

x

1

)

3

=140

Answer 2

Find the least common denominator or LCM of the two denominators:

LCM of 3 and 27 is 27

Next, find the equivalent fraction of both fractional numbers with denominator 27

For the 1st fraction, since 3 × 9 = 27,

1

3

=

1 × 9

3 × 9

=

9

27

Likewise, for the 2nd fraction, since 27 × 1 = 27,

1

27

=

1 × 1

27 × 1

=

1

27

Add the two like fractions:

9

27

+

1

27

=

9 + 1

27

=

10

27

So, 1/3 + 1/27 = 10/27