Question

LCM of two distinct natural numbers is 211. What is their HCF?

Answer 1

We can check that 211 is a prime number and so it is divisible by 1 and 211 only.

In other words, its only positive divisors are 1 and 211.

So the possible pairs of numbers whose L.C.M. can be 211 are: (1, 211) or (211, 211)

Now, we can clearly see that in the first case, the H.C.F. of the two numbers is 1, whereas in the second case, the H.C.F. of the two numbers is 211, but since it has been mentioned that the numbers are distinct, so we leave out the second possibility and hence the H.C.F. becomes 1.


plz Mark as brainlaint.....

Answer 2

We can check that 211 is a prime number and so it is divisible by 1 and 211 only.

In other words, its only positive divisors are 1 and 211.

So the possible pairs of numbers whose L.C.M. can be 211 are: (1, 211) or (211, 211)

Now, we can clearly see that in the first case, the H.C.F. of the two numbers is 1, whereas in the second case, the H.C.F. of the two numbers is 211, but since it has been mentioned that the numbers are distinct, so we leave out the second possibility and hence the H.C.F. becomes 1.

I hope this will help you

If not then comment me