LCM of two numbers is 14 times of there HCF.The sum of LCM and HCF is 600.If one number is 280, then find the other number
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Answered by
1
let HCF = x
then LCM = 14x
sum of HCF n LCM is 600, so
15x=600
so x= 40
14× x × x = 280... reqd no.
reqd no. = 14×40×40/280 =80ans...
hope this will help you...
then LCM = 14x
sum of HCF n LCM is 600, so
15x=600
so x= 40
14× x × x = 280... reqd no.
reqd no. = 14×40×40/280 =80ans...
hope this will help you...
Answered by
1
let the HCF of the numbers be x.
the LCM of the numbers = 14x
the sum of the HCF and LCM = 600
HCF of the numbers = 40 and
LCM of the numbers = 14*40 = 560
one number = 280, let the other number be y.
HCF * LCM = product of two numbers
thus the other number is 80.
hope this helps you.
the LCM of the numbers = 14x
the sum of the HCF and LCM = 600
HCF of the numbers = 40 and
LCM of the numbers = 14*40 = 560
one number = 280, let the other number be y.
HCF * LCM = product of two numbers
thus the other number is 80.
hope this helps you.
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