Math, asked by yatharthvasania5081, 11 months ago

Lcm of two prime numbers x and y(x>y) is 161. The value of 3y-x is:

Answers

Answered by NDbrainly
0

Step-by-step explanation:

x and y are two prime numbers.

Given,

LCM(x,y)=161

so, one of x and y is 1and other one is 161

let, x =1and y = 161

there for,

3y - x = 3×161 - 1 = 483 - 1 = 482

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Answered by kalyankanwar33
0

Answer:

Step-by-step explanation:

LCM of two prime numbers X and Y the answer is 161.

3y-x=161

3y=161+x

3y=162

Y=162 divided by 3

the answer is 54

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