Question

le
The total energy of a satellite of mass m orbiting with a critical orbital
speed v is
(a) – mu2
O) -- Mu? (c) mu2
(d) mu?.​

Answer 1

Answer:

option a is correct

I guess

Answer 2

The total energy of a satellite is - 1/2 mv²

Explanation:

The total energy of the satellite is given as:

E = Potential energy + Kinetic energy

The potential energy is given by the formula:

P.E = - (GMm)/r = - mv²

The kinetic energy is given by the formula:

K.E = 1/2 mv²

Since, the satellite is in critical orbital  speed.

Thus, v = √((GM)/r)

Now, the total energy is:

E = - mv² + 1/2 mv²

∴ E = - 1/2 mv²