Lead balls of diameter 6 CM are dropped into a cylindrical vessel of diameter 24 cm and height 16cm one fourth filled with water. Find the number of red balls that should be dropped into the cylindrical vessel so that the vessel is full and no water overflows.
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this is your answer bro
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Its most probably wrong.g
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The remaining volume is 3/4...Whichh I thinkk needs to bee taken out..and then the number of balls should be taken outt..
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48 lead balls would be required to fill the water to the top
Given diameter of vessel is 24 cm
Radius would be 24/2 = 12 cm
The given height of vessel is 16 cm
The volume of a cylinder is given by
V = πr²h = 3.14* 12*12*16 = 7234.56 cm³
One fourth of vessel is already filled with water.
Hence, remaining volume is 3/4th of total volume
= 5425.92 cm³
Diameter of given lead ball is 6 cm
Radius of the ball would be 6/2 = 3 cm
The volume of the ball would be (4/3) *πr³
V = (4/3) *3.14* 3*3*3 = 113.04 cm³
The number of balls required would be 5425.92 cm³/ 113.04 cm³ = 48
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