Question

lead nitrate to form a lead oxide and nitrogen dioxide and oxygen to this reaction I have procedure​

Answer 1

2 Pb(NO3)2 (s) → 2 PbO (s) + 4 NO2 (g) + O2 (g)

There are 2 moles of lead on each side, 4 moles of nitrogen, and 12 moles of oxygen.

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Answer 2

Answer:

Explanation:

2 Pb(NO3)2 (s) → 2 PbO (s) + 4 NO2 (g) + O2 (g)