Question

prove Pythagoras theorem​

Answer 1

To Prove- AC2=AB2+BC2</p >

Proof for Pythagoras Theorem

For this we drop a perpendicular BD onto the side AC

We know, △ADB∼△ABC

Therefore, ADAB=ABAC (Condition for similarity)

Or, AB2=AD×AC……..(1)

Also, △BDC∼△ABC

Therefore, CDBC=BCAC (Condition for similarity)

Or, BC2=CD×AC……..(2)

Adding the equations (1) and (2) we get,

AB2+BC2=AD×AC+CD×AC

AB2+BC2=AC(AD+CD)

Since, AD + CD = AC

Therefore, AC2=AB2+BC2

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Answer 2

Answer:

Step-by-step explanation:

It is u r answer