Lead sphere of diameter 6cm are dropped into a cylindrical beaker containing some water and are fully submerged. The diameter of the beaker is 18 cm and the rise in the level of water is 40cm. The number lead sphere dropped in the water is
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diameter of sphere=6cm
radius =3cm
volume=4/3 πr^3
diameter of beaker=18cm
radius of beaker=9cm
rise in water level=40cm
volume =πr^2h
no. of lead shots req.= volume of beaker/volume of lead shots.
=90
radius =3cm
volume=4/3 πr^3
diameter of beaker=18cm
radius of beaker=9cm
rise in water level=40cm
volume =πr^2h
no. of lead shots req.= volume of beaker/volume of lead shots.
=90
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