Question

Leargest number that divides 245 and 1029 leaving remainder 5 in each case.

Answer 1

The two numbers are 245 and 1029. You want the largest number that divides the two numbers leaving a remainder of 5 in each case. First subtract 5 from 245 and 1029 to get.
245 - 5 = 240.

Answer 2

so, 1029-5=1024 and 245-5=240
So we need to find HCF
using edl
a=bq+r
a=1024 and b=240
1024=240×4+64
here r ≠ 0
240=64×3+48
here also r ≠ 0
64=48×1+16
here also r ≠ 0
48=16×3+0
here r=0
so, HCF of (1024,240)=16
That means that 16 is the largest number that divides 245 and 1029 which leaves the remainder 5
I HOPE THIS WILL MARK ME BRAINLIEST