Least value of n such that the sum 2+5+8+..........+n exceeds 1000
Pls give the procedure
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Answer:
According to A.P
tn= a+(n-1)d
2+5+8+..........+n exceeds 1000
a= 2 d= 3
Neither 1000 be in this order so check 1003
1001 = 2+(n-1)3
1001 = 2+3n-3
1001 = 3n-1
1001+1 = 3n
1002 = 3n
1002/3 =n
n=334
therefor 1001 be n exceeds 1000
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