leela walks 8m west and 15m north to reach the opposite corner of a rectangular field.Lovleen walked from the same point diagonally to the opposite corner .What is the distance walked by Loveleen?
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Answered by
66
Here is the Solution :
If we draw a Diagram of the data, We will have a Right angled triangle,
Where Hypotenuse is on NW - SE side, And 8m is on x - axis and 15 m on y -axis,
Now, Since it's a Right angle triangle, and we have lengths of 2 sides, Let us calculate Hypotenuse using Pythagoras Theorem,
=> 8² + 15² = Hyp²
=> 64 + 225 = Hyp²
=> 289 = Hyp²
=> +17 or -17 = Hyp, But side can't be negative, So Hypotenuse is +17,
Loveleen walked on the Hypotenuse, So eventually, He walked 17m !
Therefore the answer for your Question is 17m,
Hope you Understand, Have A Great Day,
Thanking you, Bunti 360 !
If we draw a Diagram of the data, We will have a Right angled triangle,
Where Hypotenuse is on NW - SE side, And 8m is on x - axis and 15 m on y -axis,
Now, Since it's a Right angle triangle, and we have lengths of 2 sides, Let us calculate Hypotenuse using Pythagoras Theorem,
=> 8² + 15² = Hyp²
=> 64 + 225 = Hyp²
=> 289 = Hyp²
=> +17 or -17 = Hyp, But side can't be negative, So Hypotenuse is +17,
Loveleen walked on the Hypotenuse, So eventually, He walked 17m !
Therefore the answer for your Question is 17m,
Hope you Understand, Have A Great Day,
Thanking you, Bunti 360 !
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Answered by
15
Answer:
17m
Step-by-step explanation:
base square = 8m
perpendicular square = 15m
hypotenuse square = base sq. + perpendicular sq.
8 + 15
8×8 +15×15
64 + 225
289
17 × 17(square root of 289)
therefore:Distance walked by Loveleen is 17m.
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