Question

Leena's father is thrice as old as leena. after 12 years he will be just twice his daughter. find their present ages.

Answer 1

Let Leena's age be 'x'
Leena's father age = 3x

After 12 years,
Leena's age = x + 12
Leena's father age = 3x + 12

Then,

2(x + 12) = 3x + 12
2x + 24 = 3x + 12
2x - 3x = 12 - 24
-x = -12
x = 12

Leena's age = 12 years
Leena's father age = 3(12)
= 36

Answer 2

Let the age of leena= x years
Age of Leena's father = 3×x
=3x years
After 12 years
Age of leena=x+12
Age of Leena's father = 3x+12
According to question
3x+12=2×(x+12)
3x+12=2x+24
3x-2x= -12+24
x = 12
So,age of leena = 12years
Age of Leena's father = 3(12)
= 36years