Question

Lena is 6 year older than her brother Ajay if the sum of their age is 28 years old and their percentages

Answer 1

Answer:

Let the age of Ajay be 'x'

This implies that Lena is 6 years older than Ajay. Which means that Lena has an age span of x + 6.

It is given that, Sum of their ages is 28.

So on applying the sum we get,

=> x + x + 6 = 28

=> 2x + 6 = 28

=> 2x = 28 - 6

=> 2x = 22

=> x = 11 years

Hence the age of Ajay is 11 years.

This implies that Lena is 6 years older than Ajay.

Hence Lena's age would be: 11 + 6 which is 17 years.

Hence Ajay is 11 years old and Lena is 17 years old.

Coming to percentage measure,

Let us assume the percentage to be taken is to their final ages.

=> Lena's age Percentage= 17 / 28 * 100 %

=> Lena's Age percentage = 0.6071 * 100 % = 60.71 %

Ajays age percentage would be:

=> Ajay's age percentage = 11 / 28 * 100 %

=> Ajay's age percentage = 0.3928 * 100 % = 39.28 %

Hence Ajay's percentage is 39.28% and Lena's Age is 60.71%.

Answer 2

Let Ajay be x years old

Lena is x + 6 years old

Solve x:

x + (x + 6) = 28

x + x + 6 = 28

2x + 6 = 28

2x = 22

x = 11

Find their age:

Ajay = x = 11 years old

Lena = x + 6 = 11 + 6 = 17 years old

Find their percentage:

Ajay = 11/(11 + 17) x 100  = 39.29% of their total age

Lena = 17/(11 + 17) x 100 = 60.71% of their total age

Answer: Ajay is 11 and Lena is 17 years old. Ajay is 39.29 of their total age and Lena is 60.71% of their total age.