Question

length=15m , breadth=6m , height=9dm pls find the t.s.a

Answer 1

Answer:

Step-by-step explanations

Ok

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{T.S.A\:of\:cuboid=217.8\:cm}^{2}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{given : }} \\ : \implies \text{Length(l) = 15 \: m} \\ \\ : \implies \text{Breadth(b) = 6\: m} \\ \\ : \implies \text{Height(h) = 0.9 \: m} \\ \\ \red{ \underline \bold{to \: find : }} \\ : \implies \text{T.S.A \: of \: cuboid = ? }$

• According to given question :

$\bold{as \: we \: know \: that} \\ : \implies \text{T.S.A \: of \: cuboid} = 2(lb + bh + hl) \\ \\ : \implies \text{T.S.A \: of \: cuboid} = 2(15 \times 6 + 6 \times 0.9 + 0.9 \times 15) \\ \\ : \implies \text{T.S.A \: of \: cuboid} = 2(90 + 5.4 + 13.5) \\ \\ : \implies \text{T.S.A \: of \: cuboid} = 2 \times 108.9 \\ \\ \green{: \implies \text{T.S.A \: of \: cuboid = 217.8 \:{cm}}^{2} } \\ \\ \purple {\text{some \: formula \: related \: to \: this \: topic}} \\ \pink {\circ \: \text{L.S.A\: of \: cuboid = }2(l + b) \times h} \\ \\ \pink {\circ \: \text{Volume \: of \: cuboid = }l \times b \times h}$