Question

Length
ABCD or
Gide
of
16
and
diagonals of
cm
and
perimeter
thombus
rind the
cm
hobus​

Answer 1

Answer:

10 cm

Step-by-step explanation:

⇒ Let ABCD be the rhombus and AC and BD bisect at point O. AC = 16cm and BD = 12cm.

⇒ We know that the diagonals of rhombus bisect at right angles.

⇒ AO= 2/16

=8cm

⇒ BO= 21/2

=6cm

By using Pythagoras theorem,

⇒ AB^2=AO^2 +BO^2

⇒ AB^2=8^2+6^2

⇒ AB^2 =64+36

⇒ AB ^2=100

⇒ AB^2= 100

⇒ AB=10cm

∴ Side of a rhombus is 10cm

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