Length and breadth of a bulletin board are r cm and t cm respectively.
a)what will be the length in cm of the aluminum strip required to frame the board. If 10 cm extra strip is required to frame it properly.
b) If x nails are used to repair 1 board . How many nails will be required to repair 15 such boards.
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Answer:
Perimeter of the bulletin board
= 2(r+t)cm
Area of the bulletin board
= rt cm2
(i) Length (in cm) of the aluminium strip required to frame the board = Perimeter + extra strip = 2(r+t)+10cm
(ii) Repairing 1 board requires x nails.
∴
Number of nails required to repair 15 boards =
15x
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