length and breadth of a rectangular field in in the ratio 7: 4. If its perimeter is 2200m, find its dimensions.
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2
☆ Solution ☆
Given :-
- The length and breadth of a rectangular field in the ratio 7 : 4.
- The perimeter of the rectangle is 2200 m.
To Find :-
- The dimensions of the rectangle.
Step-by-Step-Explaination :-
Let,
- The ratios be 7x and 4x
As we know that :-
Perimeter of the rectangle = 2 ( length + breadth )
Where,
- Perimeter of the rectangle = 2200 m
- Length of the rectangle = 7x
- Breadth of the rectangle = 4x
Putting the respective value,
2200 = 2 ( 7x + 4x )
2200 = 2 × 11x
2200 = 22x
x = 2200/22
x = 100
Thus,
The value of x is 100.
Therefore,
The length of the rectangle = 7x = 7 × 100 = 700
The breadth of the rectangle = 4x = 4 × 100 = 400
Hence,
The length of the rectangle = 700m
The breadth of the rectangle = 400 m
Answered by
1
Explanation:
ratio of the length and Breadth= 7:4
or,7x : 4x
Perimeter = 2200m= 2(L+B)
2(7x+4x) = 14x+8x = 22x = 2200m
x= 2200/22= 100
therefore, length = 7x = 700 m
Breadth= 4x= 400 m ans.
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