Question

Length breadth and height of a box are 24.0cm 18.6 cm and 6.0cm respectively.find the maximum percentage error in estimate of volume

Answer 1

Answer:

2.6%

Explanation:

Given that,

length =24 cm

width=18.6 cm

height= 6cm

then,

maximum error can be,

\frac{delta \: v}{v} = \frac{delta \: l}{l } + \frac{delta \: w}{w } + \frac{delta \: h}{h}vdeltav=ldeltal+wdeltaw+hdeltah

putting the values,

\frac{delta \: v}{v} = \frac{0.1}{24} + \frac{0.1}{18.6} + \frac{0.1}{6}vdeltav=240.1+18.60.1+60.1

=0.0041+0.0053+0.0166

= 0.026

for percentage, multiply hundred

so,

= 0.026×100