Length of a diagonal of a rectangle is 10 cm. Its length is 4/3 times its breadth. Find the area of the square whose perimeter is equal to this rectangle.
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Answer:
Area of Square = 49cm²
Step-by-step explanation:
Let the breadth be x cm,
and the length be 4x/3 cm.
So, x²+(16x²/9) = 10²
=> 25x²/9 = 10²
=> (5x/3)² = 10²
=> 5x/3 = 10
=> x = 6cm
Breadth = 6cm
Length = 8cm
Perimeter = 28cm
Side of Square = 7cm
Area of Square = 49cm²
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