length of a rectangle exceeds its breadth by 6m. If its perimeter is 64m then find its length and breadth
Answers
Answered by
63
Answer:
let the breadth be x
length =x+6
ATQ, 2(x+x+6)=64
2x+6=64/2
2x=32-6
x=13
breadth. 13
length 19
Answered by
88
Answer :-
Length of the recatangle is 19 m and
breadth of the rectangle is 13 m.
Solution :-
Let the breadth of the rectangle be x
Length of the rectangle = exceeds breadth by 6 m = (x + 6)
Given
Perimeter of the rectangle = 64 m
⇒ 2(Length + Breadth) = 64
⇒ 2(x + x + 6) = 64
⇒ 2(2x + 6) = 64
⇒ 2x + 6 = 64/2
⇒ 2x + 6 = 32
⇒ 2x = 32 - 6
⇒ 2x = 26
⇒ x = 26/2
⇒ x = 13
Breadth = x = 13 m
Length = (x + 6) = (13 + 6) = 19 m
Therefore length of the recatangle is 19 m and breadth of the rectangle is 13 m.
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