Question

Length of a rectangle is 16 cm less than twice its breadth. If the perimeter of rectangle is 100cm, find its length and breadth.​

Answer 1

Answer:

Breadth = x

Length = 2x - 16

Perimeter = 100 cm

2 (2x - 16 + x) = 100

2 (2x + x - 16) = 100

2 (3x - 16) = 100

6x - 32 = 100

6x = 100 + 32

6x = 132

x = 132/6

x = 22

Hence, length = 2x - 16

= 2 × 22 - 16

= 44 - 16

= 28 cm

Breadth = x

= 22 cm

Answer 2

Required Answer :-

Let the length and breadth of the given rectangle bs "l" and "b".

We are given that length of the rectangle is 16 cm less than the twice it's breadth. This mean ,

• l = 2b - 16 cm

Perimter of a rectangle is given by ,

• P = 2( l + b) [here l is length and b is breadth of the rectangle]

We are given that the perimeter of rectangle as 100 cm.

➙ 100 = 2 ( l + b )

From eq(1) ,

➙ 100 = 2 [ (2b - 16) + b ]

➙ 100 = 2 [ 3b - 16]

➙ 100 = 6b - 32

➙ 100 + 32 = 6b

➙ 132 = 6b

➙ b = 132/6

➙ b = 22 cm

Now , From eq(1) ;

➙ l = 2b - 16

➙ l = 2(22) - 16

➙ l = 44 - 16

➙ l = 28 cm

Hence ,

• The length and breadth of the given rectangle are 22 cm and 28 cm.