Question

length of a rectangle is 20 more then 3 times of it breadth if perimeter of rectangle is 60m then find a linear equation this ​

Answer 1

Answer:

Let the breadth be x

then length be 3x+20

perimeter

2(x+3x+20)=60.

Answer 2

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Required eqⁿ is 3n - m + 20 = 0.

Step-by-step explanation:

Given :-

Length of a rectangle is 20 more then 3 times of it's breadth if perimeter of rectangle is 60 m.

To Find :-

Linear equation for this?

Solution :-

Let length of rectangle be m and breadth of rectangle be n.

According to the given question;

Length of a rectangle is 20 more then 3 times of it's breadth if perimeter of rectangle is 60 m.

Therefore;

➙ Length = 3(Breadth) + 20

➙ m = 3n + 20

➙ 0 = 3n + 20 - m

We can write it as;

➙ 0 = 3n - m + 20

➙ 3n - m + 20 = 0

So, required equation is 3n - m + 20 = 0.

Learn More :-

Perimeter of any figure is calculated by sum of its all sides.

Perimeter of square = 4 × side

Area of square = (side)²

Perimeter of equilateral ∆ = 3 × side

Area of equilateral ∆ = √3/4 (side)²

Perimeter of rhombus = 4 × side

Area of rhombus = ½ × d₁ × d₂

Perimeter of circle = 2πr

Area of circle = πr²

Perimeter of rectangle = 2(l + b)

Area of rectangle = l × b

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Hope this helps you ❤❤