Question

length of a rectangle is 5 more than the width of the rectangle the perimeter of the rectangle is 38 cm find the length and the width of the rectangle​

Answer 1

Answer: 84cm^2

Step by step explanation:

We know that,

▪️ Perimeter of rectangle= 2(l+b)

▪️ Let the breadth be x ▪️

=> 38= 2(x+5+x)

=> 38/2=2x+5

=> 19- 5 = 2x

=> 14=2x

=> x=7 cm

therefore,

breadth= 7cm

length= 12cm


Area of rectangle => l × b

=> 12 × 7
=> 84 cm^2

Answer 2

$\huge\bf\boxed{\boxed{\boxed{\red{\mathfrak{QUESTION \: : }}}}}$

$\bf\green{\mathbb{LENGTH \: OF \: A \: RECTANGLE \: IS }}$

$\bf\green{\mathbb{5 \: MORE \: THAN \: THE \: WIDTH}}$

$\bf\green{\mathbb{OF \: THE \: RECTANGLE.. \: THE \: PERIMETER}}$

$\bf\green{\mathbb{OF \: THE \: RECTANGLE \: IS \: 38 \: CM}}$

$\bf\green{\mathbb{FIND \: THE \: LENGTH \: AND \: THE}}$

$\bf\green{\mathbb{WIDTH \: OF \: THE \: RECTANGLE...}}$

$\huge\bf\boxed{\boxed{\boxed{\orange{\mathfrak{ANSWER \: : }}}}}$

now here we have breadth = X cm

so length will be ( 5 + X )cm

$\large\bf\boxed{ALSO \: PERIMETER \: = \: 38cm}$

but perimeter of rectangle = 2(l+b)

=> 38 = 2(5+X+X)

=> 5+2x= 19

=> 2x=14

$\large\bf\boxed{ \: X \: = \: 7}$

$\huge\bf\boxed{\boxed{\boxed{\pink{\mathfrak{HENCE }}}}}$

breadth= 7cm

$\large\bf\boxed{i.e \: B = 7cm}$

and length = 7+5 =12cm

$\large\bf\boxed{i.e \: l = 12cm}$

also area = l×b

=> A = 12×7

$\large\bf\boxed{ \: A = 84 sq.cm}$

$\huge\bf\boxed{\boxed{\boxed{\purple{\mathfrak{VAMPIRE }}}}}$