Question

Length of a rectangle is 5 times its breadth. If the length of the field is 140 cm. Find its perimeter.​

Answer 1

Given :

• Length of a rectangle is 5 times it's breadth

• Length of the field is 140 cm

To find :

• Perimter of the rectangular field

Solution :

Let the breadth of the rectangle be 'x' , then length of the rectangular field becomes '5x'

But we are given that length of the rectangular field as 140 cm.

$\\ : \implies \sf \: 5x = 140 \: cm \\ \\ \\ : \implies \sf \: x = \frac{140 \: cm}{5} \\ \\ \\ : \implies \boxed{\underline{\sf {\: x = 28 \: cm}}}$

Then breadth(x) = 28 cm and Length = 140 cm

The perimeter of a rectangle is given by ,

$\star\large{\boxed{\purple{\sf{Perimeter\:of\:a\:rectangle=2(l+ b)}}}}$

$\\ :\implies \sf Perimeter = 2(28\:cm+140\:cm)\\ \\ \\ :\implies\sf Perimeter=2(168\:cm)\\ \\ \\ :\implies{\boxed{\underline{\sf {Perimeter=336\:cm}}}}$

Hence , The perimeter of the rectangular field is 336 cm.

Answer 2

GIVEN:-

• Length(l) of a rectangle = 5 times breadth(b) of the rectangle.
• Length of the field = 140 cm.

TO FIND:-

• The perimeter of the rectangle.

SOLUTION:-

Suppose the breadth of the rectangle is x cm.

∵ Length given = 140 cm and stated that it's 5 times the breadth

∴ $\large\sf\color{red}{x = \dfrac{Length}{5} cm } </p><p></p><p>[tex]:\large\implies \large\sf{\dfrac{140}{5} cm}$

$: \large \rightsquigarrow\sf \pink{28 \: cm} \: \green \bigstar$

$☯\underline \color{magenta}{\boldsymbol{According\: to \:the\: Formula :}} </p><p>$

$\huge\color{lime}\bigstar \huge \boxed{ \sf \gray{Perimeter = 2(l+b)}}$

$\huge\therefore \sf \red{P = 2(140 + 28)}$

$: \large \implies \sf \gray{P = 2 × 168}$

$: \large \rightsquigarrow\sf \color{fuchsia}{P = 336 \: cm} \: \green \bigstar$

ANSWER:-

• The perimeter of the rectangle = 336 cm.