Question

length of a rectangle is 8m less than twice its breadth . if the perimeter of the rectangle is 56m, find its length and breadth

Answer 1

breadth=x m
length=(2x-8) m
perimeter= 2(length+breadth)
56=2(x+2x-8)
56=2(3x-8)
28=3x-8
3x=36
x=12
Therefore, length=12 m
& breadth= 2(12)-8=24-8=16 m

Answer 2

let breadth=x
length=2x-8
perimeter=56
2(L+B)=56
2(2x-8+x)=56
2(3x-8)=56
3x-8=28
3x=36
x=12
B=12,L=2(12)-8=16